Название | Smith's Elements of Soil Mechanics |
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Автор произведения | Ian Smith |
Жанр | Отраслевые издания |
Серия | |
Издательство | Отраслевые издания |
Год выпуска | 0 |
isbn | 9781119750413 |
Determine the quantity of flow per unit area in mm3/s, and the excess hydraulic heads at the sand/coarse silt and the coarse silt/fine silt interfaces.
Solution:
Taking the top of the gravel as datum:
Head of water due to artesian pressure = 15.5 m
Head of water due to groundwater = 3 × 4 + 1 = 13 m
Therefore, excess head causing flow = 15.5 − 13 = 2.5 m.
This quantity of flow is the same through each layer.
Excess head loss through fine silt:
Therefore,
Excess head loss through coarse silt:
Excess head loss through fine sand:
Excess head at interface between fine and coarse silt
Excess head at interface between fine sand and coarse silt
2.15.4 Seepage through soils of different permeabilities
When water seeps from a soil of permeability k1 into a soil of permeability k2, the principle of the square flow net is no longer valid. If we consider a flow net in which the head drop across each figure, Δh, is a constant then, as has been shown, the flow through each figure is given by the expression:
(2.36)
If Δq is to remain the same when k is varied, then b/l must also vary. As an illustration of this effect, consider the case of two soils with k1 = k2/3.
Then
and
(2.37)
i.e.
If the portion of the flow net in the soil of permeability k1 is square, then:
The effect on a flow net is illustrated in Fig. 2.31.
Fig. 2.31 Effect of variation of permeability on a flow net. (a) k2 > k1. (b) k2 < k1.
Fig. 2.32 Flow across an interface when the flow lines are at an angle to it.
2.15.5 Refraction of flow lines at interfaces
An interface is the surface or boundary between two soils. If the flow lines across an interface are normal to it, then there will be no refraction and the flow net appears as shown in Fig. 2.31. When the flow lines meet the interface at some acute angle to the normal, then the lines are bent as they pass into the second soil.
In Fig. 2.32, let RR be the interface of two soils of permeabilities, k1 and k2. Consider two flow lines, f1 and f2, making angles to the normal of α1 and α2 in soils 1 and 2, respectively.
Let f1 cut RR in B and f2 cut RR in A.
Let h1 and h2 be the equipotentials passing through A and B, respectively, and let the head drop between them be Δh.
With uniform flow conditions, the flow into the interface will equal the flow out. Consider flow normal to the interface.
In soil (1):
Fig. 2.33 Flow net for seepage through two soils of different permeabilities.
Similarly, it can be shown that, in soil (2):
Now q1 = q2,
(2.38)
A flow net which illustrates the effect is shown in Fig. 2.33.
Exercises
Exercise 2.1
In a falling head permeameter test on a fine sand, the sample had a diameter of 76 mm and a length of 152 mm with a standpipe of 12.7 mm diameter. A stopwatch was started when h was 508 mm and read 19.6 s when h was 254 mm. The test was repeated for a drop from 254 to 127 mm and the time was 19.4 s.
Determine an average value for k in m/s.
Answer 1.5 × 10−4 m/s
Exercise