Название | Algebra I All-in-One For Dummies |
---|---|
Автор произведения | Mary Jane Sterling |
Жанр | Математика |
Серия | |
Издательство | Математика |
Год выпуска | 0 |
isbn | 9781119843061 |
A. Rounding
35
36
Practice Question Answers and Explanations
1 5. First do the subtraction in the parentheses. Then multiply the result by 3. Finally, add 14.
2 77. Work inside the brackets first. Perform the two operations in the parentheses. Then perform the multiplications on the two results. Add the products. Then multiply that result by 4. Finally, subtract 11.
3 180. Multiplying by the 5 outside the braces will come last. First, do the subtraction in the parentheses. Then add inside the brackets. Multiply that result by 8, and then subtract 4. Finally, multiply by 5.
4
5 –56. Working inside the absolute value bars, first do the subtraction in the parentheses, multiply the difference by 3, and then subtract the product from 6. Find the absolute value of the result before multiplying by 5. Then subtract the product from 4.
6 8. Work on the numerator and denominator separately — leaving the division for the last step. In the numerator, do the subtraction in the first parentheses and do the multiplication in the last term. Multiply the remainder by 5. Then subtract the second term from the first. In the denominator, do the subtraction under the first radical. Then look at the radical-within-the-radical and do the addition. Evaluate the two radical values you’ve formed. Next, find the difference under the remaining radical and evaluate it. Perform the subtraction in the denominator — and, finally, divide.
If you’re ready to test your skills a bit more, take the following chapter quiz that incorporates all the chapter topics.
7
8
9
10 –5.
11
12
13 47. Regroup so that the first two numbers are together. Their sum is 0!
14 5. Regroup so that the second two numbers are together.
15 70. Regroup so that the first two numbers are together. The fraction reduces to make the multiplication easier.
16 110. Regroup so that the second two numbers are together. The multiplication is simple!
17 5. Switch the order of the second and third numbers.
18 470. Switch the order of the second and third numbers.
19 78. Switch the order of the second and third numbers.
20 8. Switch the order of the second and third numbers.
21 560. There’s a lot of switching that goes on here to make the problem easier. Your goal is to be able to multiply fractions times numbers that will eliminate their denominators. In this particular problem, I’m bringing the