Mathematics for Enzyme Reaction Kinetics and Reactor Performance. F. Xavier Malcata

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Название Mathematics for Enzyme Reaction Kinetics and Reactor Performance
Автор произведения F. Xavier Malcata
Жанр Химия
Серия
Издательство Химия
Год выпуска 0
isbn 9781119490333



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rel="nofollow" href="#ulink_3c61aac4-8087-5f6c-823e-1945478da1c8">Eq. (3.19); algebraic manipulation transforms Eq. (3.97) to

      (3.98)equation

      Equation (3.95) also leads to a number of other useful relationships; one of the most famous starts from vector w, defined as

      (3.100)equation

      whereas combination with Eq. (3.55) leads to

      (3.102)equation

      where Eq. (3.99) was again invoked – so the length of a difference of vectors equals the square root of its scalar product by itself. In view of Eq. (3.70), one may rewrite Eq. (3.101) as

      (3.103)equation

      and a second application of the said distributive property conveys

      (3.104)equation

      insertion of Eq. (3.55) supports transformation to

      (3.105)equation

      whereas application of Eq. (3.58) further justifies

      (3.108)equation

      under such circumstances; this is but Pythagoras’ theorem as per Eq. (2.431), with w playing the role of hypotenuse, and u and v playing the roles of sides of the right angle. This is illustrated in Fig. 3.3f in terms of sides u and v, with hypotenuse w generated in Fig. 3.3g as vector connecting the extreme points of u and v . The said theorem was proven previously based on Newton’s expansion of a difference, see Eqs. (2.432) and (2.433); it is possible to resort to a similar expansion of its conjugate, as illustrated in Fig. 3.3h. Two squares are accordingly considered therein – one with side a + b, and a smaller one with side c that is rotated as much as necessary to have its four corners simultaneously touch the sides of the original square; this originates four right triangles, all with hypotenuse c, and sides a and b. The area of the larger square is (a + b)2, which may in turn be subdivided into the area of the smaller square, c2, plus the areas of four identical triangles – each one accounting for ab/2, according to

      (3.109)equation

      expansion of the left‐hand side following Newton’s binomial, coupled with replacement of 4/2 by 2 in the right‐hand side, yields

      (3.110)